Calculator Inputs
Example Data Table
These examples show charge, deposited mass, and gas volume across common electrolysis situations.
| Example | Current (A) | Time (min) | Molar Mass (g/mol) | n | Efficiency (%) | Charge (C) | Mass (g) | Gas Volume (L) |
|---|---|---|---|---|---|---|---|---|
| Copper plating | 2.5 | 60 | 63.546 | 2 | 92 | 9,000.00 | 2.7266 | 0.961742 |
| Silver deposition | 1.2 | 45 | 107.8682 | 1 | 95 | 3,240.00 | 3.4411 | 0.715034 |
| Hydrogen generation | 3 | 30 | 2.0159 | 2 | 90 | 5,400.00 | 0.05077 | 0.564501 |
Formula Used
Faraday electrolysis calculations link electrical charge to chemical change. The calculator applies efficiency to separate actual output from theoretical output.
Charge: Q = I × t
Moles of electrons: n(e⁻) = Q / F
Useful charge with efficiency: Q(useful) = Q × efficiency
Moles of product: n(product) = Q(useful) / (F × z)
Mass of product: m = n(product) × molar mass
Gas volume: V = n(product) × gas molar volume
Coating volume: volume = mass / density
Coating thickness: thickness = volume / area
Energy: E(Wh) = (Q × cell voltage) / 3600
Here, F is Faraday’s constant, 96485.33212 C/mol, and z is the number of electrons transferred per mole of product.
How to Use This Calculator
- Choose a calculation mode based on your known values.
- Enter the product name, molar mass, electron count, and efficiency.
- Add current and time, direct charge, or a target output.
- Supply density and area when you need coating thickness.
- Enter cell voltage when you want energy consumption.
- Press calculate to place the result above the form.
- Review mass, gas volume, moles, charge, and runtime.
- Export the report as CSV or PDF when needed.
Frequently Asked Questions
1) What does a Faraday electrolysis calculator estimate?
It estimates charge, runtime, deposited mass, evolved gas volume, moles of product, and optional coating thickness or energy use from electrolysis inputs.
2) Why is electron count important?
Electron count links electrical charge to chemical output. A species needing two electrons per mole forms half as many moles as a one-electron process.
3) Why does efficiency change the answer?
Real cells lose charge through side reactions, heat, and transport limits. Efficiency reduces theoretical output to a more practical estimate for mass and gas volume.
4) When should I use direct charge mode?
Use it when your power source, coulomb counter, or experiment log already gives total charge. The calculator can still infer runtime if current is also known.
5) Can this estimate gas production?
Yes. Enter the correct electron count and gas molar volume. It works well for hydrogen, oxygen, chlorine, or similar products when conditions match your chosen molar volume.
6) Why do density and area matter for plating?
Deposited mass alone does not reveal coating thickness. Density converts mass to volume, and coated area converts that volume into an average thickness.
7) Why is actual mass lower than theoretical mass?
Theoretical mass assumes every coulomb produces the target product. Actual mass is lower whenever current efficiency is below one hundred percent.
8) Is this suitable for plant design decisions?
It is excellent for screening, teaching, and preliminary estimates. Final industrial design should still include kinetics, electrode geometry, transport losses, thermal limits, and verified plant data.