Calculate amps from voltage for field equipment. Compare DC and AC methods easily. Plan safer circuits with practical construction focused outputs.
| Scenario | System | Voltage | Power | PF | Efficiency | Estimated Amps |
|---|---|---|---|---|---|---|
| Portable heater | DC | 24 V | 240 W | 1.00 | 100% | 10.00 A |
| Site saw | Single Phase AC | 230 V | 1800 W | 0.95 | 92% | 8.93 A |
| Concrete mixer | Three Phase AC | 400 V | 5500 W | 0.88 | 90% | 10.02 A |
| Temporary resistor bank | DC | 120 V | Resistance mode | — | — | 6.00 A at 20 Ω |
DC loads: I = P ÷ V
Single-phase AC loads: I = P ÷ (V × PF × η)
Three-phase AC loads: I = P ÷ (√3 × V × PF × η)
Resistance method: I = V ÷ R
Where I is current in amps, P is real power in watts, V is voltage, PF is power factor, η is efficiency as a decimal, and R is resistance in ohms.
It shows how much electrical current a load draws at a given voltage. The answer helps with breaker selection, conductor planning, and checking whether tools or temporary site loads fit an available circuit safely.
Power factor accounts for the difference between real power and apparent power. Motors and inductive equipment often need it, because ignoring power factor can understate current and lead to weak planning decisions.
Three phase systems share power more efficiently across conductors. For the same real power and voltage class, calculated line current is usually lower than a comparable single phase supply.
You can use it for preliminary planning only. Final breaker size should follow local electrical rules, load type, duty cycle, ambient conditions, conductor rating, and equipment manufacturer requirements.
Use resistance mode when a load is best described by ohms instead of power. It works well for simple resistive circuits, heater checks, and quick verification of expected current from measured resistance.
A safety margin helps cover continuous operation, start-up effects, unknown field conditions, and design headroom. It creates a more conservative current target for planning circuits in demanding construction environments.
Yes. Lower efficiency means the equipment needs more input power to deliver the same output. That raises supply current, especially for motors, pumps, and driven construction tools.
Yes. Enter the quantity of identical loads, and the tool multiplies the per-unit current. That total can then be adjusted by your selected safety margin for a more practical site estimate.
Important Note: All the Calculators listed in this site are for educational purpose only and we do not guarentee the accuracy of results. Please do consult with other sources as well.